question.task)
?Certainly doable, but it will make everything look crowded and i guess your students will get the grips with current numbering scheme.

question.task)
?I don't have your code so I cannot test it. Your code example from above is different and it doesn't contain a question counter. Perhaps post an updated minimal example with the current status.Xiphias wrote:that did not do anything it seems.
Code: Select all
\documentclass[14pt,norsk,a4paper,twoside,article]{memoir}
\usepackage{libertine}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{babel,graphicx,varioref}
\usepackage{libertine}
\usepackage{exsheets}
\usepackage{amsmath}
\numberwithin{question}{section}
\renewcommand*{\thequestion}{\thesection.\arabic{question}}
\SetupExSheets{headings-format={\normalsize\sffamily}}
\usepackage{tasks}
\settasks{label-format={\sffamily}}
\DeclareSymbolFont{letters}{OML}{ztmcm}{m}{it}
\DeclareSymbolFontAlphabet{\mathrm}{letters}
\title{Oppgaver 2P}
\begin{document}
\chapter{Potenser og tall på Standardform}
\section{Negative tall}
\subsection{Addisjon}
\begin{question}
\begin{tasks}(3)
\task $2+(-1) $
\task $2-3 $
\task $1-3 $
\task $-3+4 $
\task $-5+2 $
\task $-1-4 $
\end{tasks}
\end{question}
\begin{question}
\begin{tasks}(3)
\task $-2+3-2 $
\task $5-1-2 $
\task $3-4-1 $
\task $-5+1-5 $
\task $3+2-1-3 $
\task $-3+(-1)-2+5 $
\end{tasks}
\end{question}
\subsection{Multiplikasjon}
\begin{question}
\begin{tasks}(3)
\task $3\cdot(-2) $
\task $(-2)\cdot 2 $
\task $(-4)\cdot (-2) $
\task $(-3)\cdot 2\cdot (-1) $
\task $3\cdot 1 \cdot (-1) $
\task $(-1)\cdot (-2) \cdot (-3)$
\end{tasks}
\end{question}
\end{document}
Code: Select all
\documentclass[14pt,norsk,a4paper,twoside,article]{memoir}
\usepackage{libertine}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{babel,graphicx,varioref}
\usepackage{libertine}
\usepackage{exsheets}
\SetupExSheets{headings-format={\normalsize\sffamily},counter-within=section}
%\DeclareTranslation{Norsk}{exsheets-exercise-name}{}
\usepackage{tasks}
\settasks{label-format={\sffamily}}
\DeclareSymbolFont{letters}{OML}{ztmcm}{m}{it}
\DeclareSymbolFontAlphabet{\mathrm}{letters}
\title{Oppgaver 2P}
\begin{document}
\chapter{math stuff}
\section{Addisjon} Regn ut% \\%Don't do that
\begin{question}
\begin{tasks}(4)
\task $2+(-1) $
\task $2-3 $
\task $1-3 $
\task $-3+4 $
\task $-5+2 $
\task $-1-4 $
\end{tasks}
\end{question}
\begin{question}{6}
\begin{tasks}(3)
\task $-2+3-2 $
\task $5-1-2 $
\task $3-4-1+1-1+1-1+1-1 $
\task $-5+1-5 $
\task $3+2-1-3 $
\task $-3+(-1)-2+5 $
%\\%Don't do that
\end{tasks}
\end{question}
\section{Multiplikasjon} Regn ut% \\%Argh
\begin{question}
\begin{tasks}
\task $3\cdot(-2) $
\task $(-2)\cdot 2 $
\task $(-4)\cdot (-2) $
\task $(-3)\cdot 2\cdot (-1) $
\task $3\cdot 1 \cdot (-1) $
\task $(-1)\cdot (-2) \cdot (-3)$
\end{tasks}
\end{question}
\end{document}
The exsheets package also hasStefan_K wrote:Code: Select all
\numberwithin{question}{section}
Code: Select all
\SetupExSheets{
counter-within = section
}
Code: Select all
\documentclass{article}
\usepackage{exsheets}
\SetupExSheets{
counter-within = section ,
counter-format = se.qu
}
\begin{document}
\section{Foo}
\begin{question}
first one
\end{question}
\begin{question}
second one
\end{question}
\end{document}
Code: Select all
\documentclass{article}
\usepackage{exsheets,tasks}
\SetupExSheets{
counter-within = section ,
counter-format = se.qu
}
\begin{document}
\section{Foo}
\begin{question}
\begin{tasks}(4)
\task one
\task two
\task three
\task four
\end{tasks}
\end{question}
\begin{question}
\begin{tasks}(4)
\task one
\task two
\task three
\task four
\end{tasks}
\end{question}
\end{document}