LaTeX.org

i solved it:
\newtheorem{theorem}[subsubsection]{Teorema}
\newtheorem{lemma}[subsubsection]{Lema}
\newtheorem{proposition}[subsubsection]{Proposición}
\newtheorem{corollary}[subsubsection]{Corolario}

now works, thank you stefan

i was wrong, i checked your way and it works!! can you tell me how to do the same with the lemmas and propositions (all sharing the same counter) . before i had this
\newtheorem{theorem}{Teorema} [subsection]
\newtheorem{lemma}[theorem]{Lema}
\newtheorem{proposition}[theorem]{Proposición ...

i was wrong, i checked your way and it works!! thank you very much

thank you, but what i want is the converse: the subsubsection must use the counter of the theorem

hi, i'm trying to put the same counter on the subsubsection that i have for theorems.
theorem 3.4.5
3.4.1 (my subsubsection name)
this is what i have and i'd like to have:
theorem 3.4.5
3.4.6 (my subsubsection name)
any ideas????
thanks